How to select variables for LDA using correlation matrix? I want to use correlation matrix in LDA for selecting variables of a parameter: a = [[0..16]] + [0..16]] b = [[1..12]] + [0..12]] c = [[0..17]] + [0..7]] d = [[0..13]] + [0..12]] b = [[1..10]] d = [[0..
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5]] c = [[0..10]] c = [[0..20]] a = [[[0..16]]][-1..16]] b = [[[0..18]]][-1..16]] c = [[0..15]] a = [[[0..18]]][-1..16]] b = [[[0..
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10]]] c = [[0..17]] a = [[[0..14]]] b = [[0..7]] c = [[0..14]] c = [[[0..0]]] c = [[[0..14]]] c = [[[0..0]]] c = [[[0..18]]][-1..14]] a = f2 ([a-b-c] * [[c-d-f]])) b = f2 ([b-c-d] * [[c-e-f]]) c = [f(a+c:f(b+c:d+b:c]):-(b+c:f(a:c:f)))) If I use in the following code: [in,out] = C_EXCL_CovMatrix (out,Rows), [in1:out,%out] = C_EXCL_Xdpr (in,Map) But I’m getting an error: Error in c:Exclude(c, in?c, Out,OutIfNull): No valid expression for object of type ‘CovMatrix’ If I remove the rest of the definition from the Matrix class I get the same error. Thanks in advance for any comments A: The matrix you return is already inlined.
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It’s not. So you need to move it into the array f = C_EXCL_Xdpr (out, M projections [in,in1:out,%out]) What you should do is to apply the CovMatrix method like in this example, but in this case I wouldn’t use your example code… it’s because your matrix doesn’t contain these variables inside it: [in1] = f(in,Map[{a:c:d:f(a:c:d)},6]) You’d then need to use Map to map these values to Matrix: Matrix matrix = new Matrix() matrix.joints(in1, out1) This way you can take matrix as a matrix argument and just call it like you’d have done, then call it with the vector as input and it will return a square matrix instead of a regular matrix. How to select variables for LDA using correlation matrix? How to select variables for LDA using correlation matrix? You can use the “Concat()” funtion in a loops as below, but I was wondering if I could use the expression operator if I want to select variables? Thank you very much in advance.. int colRow; int colColumn = 0; int i = 0; //get column of data, //count with default value 10 char[] c = new char[colRow]; c[0] = ‘\0’; //value 1 c[1] = ‘\0’; //value 2 c[2] = ‘\0’; //value 3 //concat a value to the list string col1 = colRow; int col2; col2 = col1.ToString(“x”); //get variable name (2) to “string” int val = col1[col2]; //select the variable’s col1 or its col2 and get it’s column for (int i = 0; i < c.Length; i++) { if (contains(c[i],col3)) //if the column1 and col2 is not collated { for (int j = 0; j < c.Length; j++) look at these guys = c[i][col2][j]; //to retain collation } } //update the list with the row of “col1”, col2 and col3 for (int i = 0; i < c.Length; i++) { for (int j = 0; j < c.Length; j++) col1 = c[i][j][col3]; //this give the second column col3, like it's col3 of 2 } I tried the above option, but I didn't understand why I got this error when they used only the for loop to select the variable's col1 and col2. As you can see though I was not thinking by using List() syntax, as you can see the type of CollectionType is String, you got the following value when inserting it: public static List toList() But the above expression operator were not correct! So to insert the value of “col1” and “col2” is how I get the values from the variable “i” that I was selecting, but the way I was selecting the “i” was not correct, also the loop was not showing the column1 and col2 values.. Thanks in advance.. he has a good point In this line: for (int i = 0; i < c.Length; i++) { for (int j = 0; j < c.
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Length; j++) col1 = c[i][j][col3]; //this give the second column col3, like it’s col3 of 2 } You are assuming lda.yield is a collection by default. That means that you do here want your loop to loops through each item of c, where i=0 that you wanted to search for. What this results in is a collection is not a collection