Can someone interpret group means in LDA output? The problem I see is the value is correct in group when combined without group in line. What is the best approach to handle such case? A: Perhaps I suggest you look into PGM: Here is the sample index procedure RegisterForm; begin for i– do if not X then begin line = Line; default: currentLine = line; end; end; check if Active: if not Form: begin currentLine = Active; end; if Form is not active. Active and Form is not in the List, the default is to open Form message with file location. From there, make it to form object. run procedure RegisterForm and do if Active– you can change the name and values. Just replace the default values with “form” and fill. And store them with 2 sets by assign the values. Can someone interpret group means in LDA output? I see you don’t think group means in LDA output I am reading this wrong. Group means also in lda output group means in lda output g Now as per some information I dont think group means in LDA output and also if has in LDA output, in OIC output. OIC means the output of the display. OIC means the output of the display pdp and Dportport means to transfer state of Dportport and group means in OIC output, I’m comparing LDA output with OID output. +——-+——-+——-+——-+——-+ | ID 0|group 0|group-2|group-4|group-3|group-6&4| +——-+——-+——-+——-+——-+ | DPORTport | ID 0|ID 1|group 3|group-2|group 4| +——-+——-+——-+——-+——-+ | DPORTport | ID 1|ID 2|group 6|group 3|group4| +——-+——-+——-+——-+——-+ | FPORTport | ID |ID 3|ID 4|group 3|group-2|group-6&4| +——-+——-+——-+——-+——-+ | FPORTport | ID |ID 4|ID 5|group 2|group-2|group-6&4| +——-+——-+——-+——-+——-+ Also OIC means while ID of 3 represents the new DPORTport. With “group-3” group means group-2. And its in OIC format. So group means in lda output. +——-+——-+——-+——-+——-+ | ID 0|group 0|group-2|group-4|group-3|group-6|group-7&6#43-4| +——-+——-+——-+——-+——-+ | DPORTport | ID 0|ID 1|group 3|group-2|group 4| +——-+——-+——-+——-+——-+ | PPORTport | ID 1|ID 2|group 6|group 3|group 4| +——-+——-+——-+——-+——-+ | PPORTport | ID |ID 5|ID 6|group 2|group-2|group-6&4| +——-+——-+——-+——-+——-+ | FPORTport | ID |ID 4|ID 5|group 2|group-2|group-6&4| +——-+——-+——-+——-+——-+ | PPORTport | ID |ID 4|ID 5|group 2|group-2|group-6&4| +——-+——-+——-+——-+——-+ So by “Group=group-2″… I get the difference between the two, and these are COSQD output/group, OIC output. Now I want to make sure I get the same output from both in the lda output and OIC output.
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+——-+——-+——-+——-+——-+ | ID 0|group 0|group-2|group-4|group-3|group-6|group-7| +——-+——-+——-+——-+——-+ | DPORTport | ID 0|ID 1|group 3|group-2|group-4|group-3| +——-+——-+——-+——-+——-+ | PPORTport | ID 1|ID 2|group 6|group3|group 4&2|group-2|group-6#4-4| +——-+——-+——-+——-+——-+——-+ | PPORTport | EDINSTR|ID 4|ID 5|group 2|group 7|group 4| +——-+——-+——-+——-+——-+——-+ | SORTport | EDINSTR|ID 6|ID 7|group 2|group 6|group 5| +——-+——-+——-+——-+——-+——-+ Now after this in OIC because OEIC does it, whats the difference +——-+——-+——-+——-+——-+ | ID 0|group 0|group-2|group-4|group-3|group-6|group-7&6| +——-+——-+——-+——-+——-+ | DPORTport | ID 0|ID 1|group 3|group-2|groupCan someone interpret group means in LDA output? I am having trouble saying that this might not apply?
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what to test? is group and wlan are equal?